Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 12 - Sound - Search and Learn - Page 358: 2

Answer

The car is moving at a speed of 114 m/s

Work Step by Step

We can write an expression for the frequency $f_a$ heard as the car approaches. $f_a = \frac{f}{(1-\frac{v_{car}}{v_{snd}})}$ We can write an expression for the frequency $f_r$ heard as the car recedes. $f_r = \frac{f}{(1+\frac{v_{car}}{v_{snd}})}$ Since the frequency drops by an octave, $f_a = 2f_r$. We can find the speed of the car. $f_a = 2f_r$ $\frac{f}{(1-\frac{v_{car}}{v_{snd}})} = \frac{2f}{(1+\frac{v_{car}}{v_{snd}})}$ $1+\frac{v_{car}}{v_{snd}} = 2(1-\frac{v_{car}}{v_{snd}})$ $\frac{3~v_{car}}{v_{snd}} = 1$ $v_{car} = \frac{v_{snd}}{3}$ $v_{car} = \frac{343~m/s}{3}$ $v_{car} = 114~m/s$ The car is moving at a speed of 114 m/s.
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