Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 10 - Fluids - Problems - Page 287: 44

Answer

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Work Step by Step

Follow the hint and use Bernoulli’s equation with no flow, which means $v_1=v_2=0$. Let point 1 be the initial point, and point 2 be the final point. $$P_1+\frac{1}{2}\rho v_1^2+\rho g y_1= P_2+\frac{1}{2}\rho v_2^2+\rho g y_2$$ $$P_1+\rho g y_1= P_2+\rho g y_2$$ $$P_2-P_1=\Delta P = \rho g (y_1- y_2)$$ A change in the y coordinate is the negative of the change in depth, h. Equation 10–3b refers to the depth. $$\Delta P=-\rho g \Delta y=\rho g \Delta h $$ This was to be shown.
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