Answer
The volume of fresh water that was delivered is $1.89\times 10^4~kg$
Work Step by Step
We can find the volume of sea water that was displaced by the weight of the fresh water that was delivered.
$V = (2240~m^2)(8.25~m)$
$V = 18,480~m^3$
We can find the mass of the sea water that was displaced.
$M = \rho~V$
$M = (1025~kg/m^3)(18,480~m^3)$
$M = 1.89\times 10^7~kg$
Since the weight of the displaced sea water is equal to the buoyant force, and the buoyant force is equal to the weight of the fresh water that was delivered, the mass of the fresh water that was delivered is also equal to $1.89\times 10^7~kg$. We can find the volume $V_w$ of the fresh water that was delivered.
$V_w = \frac{M}{\rho_w}$
$V_w = \frac{1.89\times 10^7~kg}{1000~kg/m^3}$
$V_w = 1.89\times 10^4~m^3$
The volume of fresh water that was delivered is $1.89\times 10^4~kg$.
