Answer
The pressure on the mountains under the ice is $2\times 10^7~N/m^2$
Work Step by Step
$P = P_0 + \rho~g~h$
where
$P$ is the pressure
$P_0$ is the atmospheric pressure
$\rho$ is the density of the ice
$h$ is the depth below the surface
We can find the pressure $P$ at the bottom of the ice as:
$P = P_0 + \rho~g~h$
$P = (1.013\times 10^5~N/m^2) + (917~kg/m^3)(9.80~m/s^2)(2000~m)$
$P = 2\times 10^7~N/m^2$
The pressure on the mountains under the ice is $2\times 10^7~N/m^2$.
