#### Answer

The spring is compressed by 0.31 meters.

#### Work Step by Step

We can find the force $F_s$ that the spring pushes up on the student.
$\sum F = ma$
$F_s-mg = ma$
$F_s = m(g+a)$
$F_s = (60~kg)(9.80~m/s^2+3.0~m/s^2)$
$F_s = 768~N$
We can find the distance that the spring is compressed when the spring is pushing with this force.
$kx = F_s$
$x = \frac{F_s}{k}$
$x = \frac{768~N}{2.5\times 10^3~N/m}$
$x = 0.31~m$
The spring is compressed by 0.31 meters.