Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 9 - Work and Kinetic Energy - Exercises and Problems - Page 228: 28


The spring is compressed by 0.31 meters.

Work Step by Step

We can find the force $F_s$ that the spring pushes up on the student. $\sum F = ma$ $F_s-mg = ma$ $F_s = m(g+a)$ $F_s = (60~kg)(9.80~m/s^2+3.0~m/s^2)$ $F_s = 768~N$ We can find the distance that the spring is compressed when the spring is pushing with this force. $kx = F_s$ $x = \frac{F_s}{k}$ $x = \frac{768~N}{2.5\times 10^3~N/m}$ $x = 0.31~m$ The spring is compressed by 0.31 meters.
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