Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 9 - Work and Kinetic Energy - Exercises and Problems: 20

Answer

During the interval 0 - 1 m, the work done is 4 J During the interval 1 - 2 m, the work done is 0 During the interval 2 - 3 m, the work done is -2 J

Work Step by Step

The work done on the particle is equal to the area under the force versus position graph. We can find the work done during the interval 0 - 1 m: $W = F~d$ $W = (4~N)(1~m)$ $W = 4~J$ We can find the work done during the interval 1 - 2 m: $W = F~d$ $W = (4~N)(0.5~m)+(-4~N)(0.5~m)$ $W = 0$ We can find the work done during the interval 2 - 3 m: $W = \frac{1}{2}(-4~N)(1~m)$ $W = -2~J$
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