# Chapter 9 - Work and Kinetic Energy - Exercises and Problems: 16

$W = -392~J$

#### Work Step by Step

We can find the work done by gravity as; $W = F\cdot d$ $W = F_x~d_x+F_y~d_y$ $W = (0)(r_{2x}-r_{1x})+(-mg)(r_{2y}-r_{1y})$ $W = 0-(25~kg)(9.80~m/s^2)(2.9~m-1.3~m)$ $W = -392~J$

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