Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 9 - Work and Kinetic Energy - Exercises and Problems - Page 228: 16


$W = -392~J$

Work Step by Step

We can find the work done by gravity as; $W = F\cdot d$ $W = F_x~d_x+F_y~d_y$ $W = (0)(r_{2x}-r_{1x})+(-mg)(r_{2y}-r_{1y})$ $W = 0-(25~kg)(9.80~m/s^2)(2.9~m-1.3~m)$ $W = -392~J$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.