Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 9 - Work and Kinetic Energy - Exercises and Problems - Page 227: 5


(a) W = -5.25 J (b) W = 0

Work Step by Step

(a) We can find the work done by the tension. $W = F\cdot d$ $W = F ~d~cos(\theta)$ $W = (15~N)(0.35~m)~cos(180^{\circ})$ $W = (15~N)(0.35~m)(-1)$ $W = -5.25~J$ (b) We can find the work done by gravity. $W = F\cdot d$ $W = F ~d~cos(\theta)$ $W = F~d~cos(90^{\circ})$ $W = F~d~(0)$ $W = 0$
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