Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

(a) We can find the work done by the tension; $W = F\cdot d$ $W = F ~d~cos(\theta)$ $W = (15~N)(2.0~m)~cos(0^{\circ})$ $W = 30~J$ (b) We can find the work done by gravity; $W = F\cdot d$ $W = F ~d~cos(\theta)$ $W = F~d~cos(90^{\circ})$ $W = F~d~(0)$ $W = 0$