Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 9 - Work and Kinetic Energy - Exercises and Problems - Page 227: 4

Answer

(a) W = 30 J (b) W = 0

Work Step by Step

(a) We can find the work done by the tension; $W = F\cdot d$ $W = F ~d~cos(\theta)$ $W = (15~N)(2.0~m)~cos(0^{\circ})$ $W = 30~J$ (b) We can find the work done by gravity; $W = F\cdot d$ $W = F ~d~cos(\theta)$ $W = F~d~cos(90^{\circ})$ $W = F~d~(0)$ $W = 0$
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