Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 9 - Work and Kinetic Energy - Exercises and Problems - Page 227: 2


$v = 110~km/h$

Work Step by Step

We know that; $KE = \frac{1}{2}mv^2$ We can equate the kinetic energy of the car and the kinetic energy of the truck to find the required speed of the car: $KE_{car} = KE_{truck}$ $\frac{1}{2}(1000~kg)v^2= \frac{1}{2}(20,000~kg)(25~km/h)^2$ $v^2 = (20)(25~km/h)^2$ $v = \sqrt{(20)(25~km/h)^2}$ $v = 110~km/h$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.