Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 42 - Nuclear Physics - Exercises and Problems - Page 1236: 23

Answer

$m = 8.36\times 10^{-8}~kg$

Work Step by Step

We can write an expression for the decay rate: $r = \frac{ln~2}{t_{1/2}}$ We can find the number of atoms $N$: $R = r~N$ $R = (\frac{ln~2}{t_{1/2}})~(N)$ $N = \frac{R~t_{1/2}}{ln~2}$ $N = \frac{(3.50\times 10^9)(5.27)(365)(24)(3600)}{ln~2}$ $N = 8.39\times 10^{17}~atoms$ We can find the mass: $m = (8.39\times 10^{17}~atoms)(60)(1.66\times 10^{-27}~kg)$ $m = 8.36\times 10^{-8}~kg$
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