Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 42 - Nuclear Physics - Exercises and Problems - Page 1236: 20

Answer

$4.57\times 10^9~~$ alpha particles are emitted.

Work Step by Step

We can find the number of atoms remaining after $t = 50~min$: $N = N_0~(0.5)^{t/(t_{1/2})}$ $N = (1.0\times 10^{10})~(0.5)^{50/100}$ $N = 7.07\times 10^9$ We can find the number of atoms remaining after $t = 200~min$: $N = N_0~(0.5)^{t/(t_{1/2})}$ $N = (1.0\times 10^{10})~(0.5)^{200/100}$ $N = 2.50\times 10^9$ We can find the number of alpha particles emitted: $(7.07\times 10^9) - (2.50\times 10^9) = 4.57\times 10^9$ $4.57\times 10^9~~$ alpha particles are emitted.
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