Answer
(a) $\lambda = 1.06\times 10^{-6}~m$
(b) $P = 1.87~W$
Work Step by Step
(a) We can find the wavelength:
$\lambda = \frac{hc}{E}$
$\lambda = \frac{(6.63\times 10^{-34}~J~s)(3.0\times 10^8~m/s)}{(1.17~eV)(1.6\times 10^{-19}~J/eV)}$
$\lambda = 1.06\times 10^{-6}~m$
(b) We can find the power output:
$P = (1.17~eV)(1.6\times 10^{-19}~J/eV)(1.00\times 10^{19}~s^{-1})$
$P = 1.87~W$
