Answer
$t = 27.4~ns$
Work Step by Step
We can find the number of excited atoms that remain:
$N = (1.00\times 10^6)-(8.0\times 10^5) = 2.0\times 10^5$
We can find the time $t$:
$N = N_0~e^{-t/\tau}$
$2.0\times 10^5 = (1.00\times 10^6)~e^{-t/\tau}$
$0.20 = e^{-t/\tau}$
$ln(0.20) = -\frac{t}{\tau}$
$t = -ln(0.20)~(\tau)$
$t = -ln(0.20)~(17~ns)$
$t = 27.4~ns$