## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

The particle would have a mass that is $~~1.4\times 10^{36}~~$ times a proton's mass.
The total energy of the two protons is $13~TeV$ We can convert this energy to units of joules: $(13\times 10^{12}~eV)(\frac{1.6\times 10^{-19}~C}{1~eV}) = 2.08\times 10^{-6}~J$ We can find the mass of a particle with this rest energy: $mc^2 = E$ $m = \frac{E}{c^2}$ $m = \frac{2.08\times 10^{-6}~J}{(3.0\times 10^8~m/s)^2}$ $m = 2.31\times 10^9~kg$ We can express this mass as a multiple of a proton's mass: $\frac{2.31\times 10^9~kg}{1.67\times 10^{-27}~kg} = 1.4\times 10^{36}$ The particle would have a mass that is $~~1.4\times 10^{36}~~$ times a proton's mass.