Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 37 - The Foundation of Modern Physics - Exercises and Problems - Page 1082: 18


$K = 75~eV$

Work Step by Step

The initial kinetic energy of the proton must be equal in magnitude to the energy lost after passing through a potential difference of $75~V$ We can find the initial kinetic energy of the proton: $K = \Delta V~q$ $K = (75~V)(1.6\times 10^{-19}~C)$ $K = 1.20\times 10^{-17}~J$ $K = (1.20\times 10^{-17}~J)(\frac{1~eV}{1.6\times 10^{-19}~J})$ $K = 75~eV$
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