#### Answer

(12m,-6m)

#### Work Step by Step

a). a=$0.75 m/s^{2}$
After t=4s, in negative y-direction,$S=ut+\frac{1}{2}at^{2}=0+0.5\times0.75\times4^{2}=6m$
After t=4s, in positive x-direction, $S=3\times4=12m$
So, position of the particle is (12m,-6m)

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Published by
Pearson

ISBN 10:
0-32160-183-1

ISBN 13:
978-0-32160-183-4

(12m,-6m)

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