## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

The friend's distance from the camera should be $~~540~cm$
We can use similar triangles to find the required distance $d$: $\frac{d}{180~cm} = \frac{15~cm}{5.0~cm}$ $d = \frac{(15~cm)(180~cm)}{5.0~cm}$ $d = 540~cm$ The friend's distance from the camera should be $~~540~cm$