Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 34 - Ray Optics - Exercises and Problems - Page 990: 15

Answer

$\theta_c = 76.7^{\circ}$

Work Step by Step

We can find the critical angle: $\theta_c = sin^{-1}~(\frac{n_2}{n_1})$ $\theta_c = sin^{-1}~(\frac{1.46}{1.50})$ $\theta_c = 76.7^{\circ}$
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