Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 34 - Ray Optics - Conceptual Questions - Page 989: 8


The object distance is between $f$ and $2f$

Work Step by Step

We can write the lens equation: $\frac{1}{f} = \frac{1}{d_o}+\frac{1}{d_i}$ For a converging lens, when the object is located at $2f$, then the image is inverted and the image has the same size as the object. If the object moves from $2f$ toward $f$, then the inverted image becomes larger than the object. Since the image is inverted and larger than the object, the object distance is between $f$ and $2f$
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