Answer
$v = 2.0\times 10^4~m/s$
Work Step by Step
We can find the required speed:
$emf =B~L~v$
$v =\frac{emf}{B~L}$
$v =\frac{1.0~V}{(5.0\times 10^{-5}~T)(1.0~m)}$
$v = 2.0\times 10^4~m/s$
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