## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

(a) $I = 0$ (b) $I = 2.0~A$
(a) We can find the current immediately after the switch closes: $I(t) = \frac{V}{R}(1-e^{-Rt/L})$ $I(t) = \frac{V}{R}(1-e^0)$ $I(t) = \frac{V}{R}(1-1)$ $I(t) = 0$ (b) We can find the current after the switch has been closed for a long time: $I(t) = \frac{V}{R}(1-e^{-Rt/L})$ $I(t) = \frac{V}{R}(1-\frac{1}{e^{Rt/L}})$ $I(t) = \frac{V}{R}(1-0)$ $I(t) = \frac{V}{R}$ $I(t) = \frac{10~V}{5~\Omega}$ $I(t) = 2.0~A$