Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 30 - Electromagnetic Induction - Exercises and Problems - Page 869: 2

Answer

$B = 0.10~T$ (into the page)

Work Step by Step

We can find the magnetic field strength: $emf =B~L~v$ $B =\frac{emf}{v~L}$ $B =\frac{0.050~V}{(5.0~m/s)(0.10~m)}$ $B = 0.10~T$ If the magnetic field is directed into the page, then there would be a force on a positive charge directed toward the left. By Lenz's law, a potential difference is induced which opposes this. Therefore, the positive charges are on the left and the negative charges are on the right.
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