Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 26 - Potential and Field - Exercises and Problems - Page 737: 9

Answer

(a) $E_x = 500~V/m$ (b) $E_x = -1000~V/m$ (c) $E_x = 500~V/m$

Work Step by Step

(a) We can find $E_x$ at the point $x = -2~cm$: $E_x = -\frac{\Delta V}{\Delta x}$ $E_x = -\frac{0-(-10~V)}{-0.03~m-(-0.01~m)}$ $E_x = -\frac{10~V}{-0.02~m}$ $E_x = 500~V/m$ (b) We can find $E_x$ at the point $x = 0~cm$: $E_x = -\frac{\Delta V}{\Delta x}$ $E_x = -\frac{10~V-(-10~V)}{0.01~m-(-0.01~m)}$ $E_x = -\frac{20~V}{0.02~m}$ $E_x = -1000~V/m$ (c) We can find $E_x$ at the point $x = 2~cm$: $E_x = -\frac{\Delta V}{\Delta x}$ $E_x = -\frac{0-(10~V)}{0.03~m-(0.01~m)}$ $E_x = -\frac{-10~V}{0.02~m}$ $E_x = 500~V/m$
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