Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 26 - Potential and Field - Exercises and Problems - Page 737: 2


$\Delta V = -5000~V$

Work Step by Step

We can find the potential difference: $\Delta V = \Delta y~E_y$ $\Delta V = (y_f-y_i)~E_y$ $\Delta V = [0.05~m-(-0.05~m)]~(-50,000~V/m)$ $\Delta V = -5000~V$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.