## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

(a) Point A has a larger electric potential than Point B. (b) The magnitude of the potential difference between Point A and Point B is $70~V$
(a) The electric field points from positions of higher potential to positions of lower potential. Therefore, A has a larger electric potential than B. (b) We can find the potential difference between A and B: $\Delta V = -E~\Delta x$ $\Delta V = -(1000~V/m)(0.070~m)$ $\Delta V = - 70~V$ The magnitude of the potential difference between A and B is $70~V$.