Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 25 - The Electric Potential - Exercises and Problems - Page 709: 8


$F=1.44 \times 10^{-3} N$

Work Step by Step

By the Work-Energy Theorem; P.E. = Work done $U=F.D$ $F=\frac{U}{D}=\frac{72 \times 10^{-6}}{5 \times 10^{-2}}=1.44 \times 10^{-3} N$ Hence, $F=1.44 \times 10^{-3} N$.
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