Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 25 - The Electric Potential - Exercises and Problems: 8

Answer

$F=1.44 \times 10^{-3} N$

Work Step by Step

By the Work-Energy Theorem; P.E. = Work done $U=F.D$ $F=\frac{U}{D}=\frac{72 \times 10^{-6}}{5 \times 10^{-2}}=1.44 \times 10^{-3} N$ Hence, $F=1.44 \times 10^{-3} N$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.