Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 25 - The Electric Potential - Exercises and Problems: 14

Answer

$8.35 \times 10^{4} volt$

Work Step by Step

Initial speed of an $He^{+}$ ion = 0 Loss in energy = Gain in energy; $e\Delta V=KE_{f}-KE_{i}$ $e\Delta |V|=\frac{1}{2}m_{He^{+}}v_{He^{+}}^{2}-0$ $\Delta |V|=\frac{\frac{1}{2}m_{He^{+}}v_{He^{+}}^{2}}{e}$ $\Delta |V|=\frac{{\frac{1}{2}4m_{p}v_{He^{+}}^{2}}}{1.6 \times 10^{-19}}$ $\Delta |V|=\frac{1}{2}\times \frac{{ 4\times 1.67 \times 10^{-27} \times(2\times 10^{6})^{2}}}{1.6 \times 10^{-19}}$ $\Delta |V|=8.35 \times 10^{4} volt$
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