## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

$4.37 \times 10 ^{4} m/s$
By the conservation of energy; Loss in energy = Gain in energy $q \Delta V=\frac{1}{2}m_{p}v_{p}^{2}$ $v_{p}=[\frac{2q\Delta V}{m}]^{1/2}$ $v_{p}=[\frac{2\times 1.6 \times 10^{-19} \times 10^{3}}{1.67\times 10^{-27}}]^{1/2}= 4.37 \times 10 ^{4} m/s$