## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

$9.0\times 10^{13}~electrons$
We can find the total charge in 2 hours: $Q = (-2.0\times 10^{-9}~C/s)(2~h)(3600~s/h)$ $Q = -1.44\times 10^{-5}~C$ We can find the number of electrons: $N = \frac{-1.44\times 10^{-5}~C}{-1.6\times 10^{-19}~C} = 9.0\times 10^{13}~electrons$