Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 22 - Electric Charges and Forces - Exercises and Problems - Page 624: 6


$mass = 2.16\times 10^{-8}~kg$

Work Step by Step

We can find the required number of protons: $\frac{1~C}{1.6\times 10^{-19}~C} = 6.25\times 10^{18}~protons$ We can find the required number of atoms: $n = \frac{6.25\times 10^{18}}{13} = 4.8\times 10^{17}~atoms$ Note that the atomic mass of aluminum is $26.98~u$ We can find the required mass of aluminum: $mass = (26.98)(1.67\times 10^{-27}~kg)(4.8\times 10^{17})$ $mass = 2.16\times 10^{-8}~kg$
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