## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson

# Chapter 22 - Electric Charges and Forces - Exercises and Problems - Page 624: 1

#### Answer

(a) Electrons have been removed from the glass rod. (b) $3.1\times 10^{10}$ electrons were removed from the rod.

#### Work Step by Step

(a) Since it is normally quite easy for electrons to move, we can assume that it is the electrons which are transferred when there is a transfer of charge. In this case, we can assume that electrons have been removed from the glass rod. (b) Since the rod has a charge of $+5.0~nC$, a charge of $-5.0~nC$ was removed from the rod. Each electron has a charge of $-1.6\times 10^{-19}~C$. We can find the number of electrons that were removed. $\frac{-5.0\times 10^{-9}~C}{-1.6\times 10^{-19}~C} = 3.1\times 10^{10}~electrons$ $3.1\times 10^{10}$ electrons were removed from the rod.

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