Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 2 - Kinematics in One Dimension - Exercises and Problems: 6

Answer

(a) Yes, the particle has a turning point at t = 1 s. (b) At t = 2 s, $x = 10~m$ At t = 3 s, $x = 16~m$ At t = 4 s, $x = 26~m$

Work Step by Step

(a) Yes, the particle has a turning point at t = 1 s. Note that at t = 1 s, the velocity is zero as it changes from a negative velocity to a positive velocity. This shows that the particle has a turning point at this time. (b) The area between the velocity versus time graph and the x-axis is equal to the displacement. From t = 0 to t = 2 s: $\Delta x = 0$ At t = 2 s: $x = x_0 + \Delta x$ $x = 10 ~m + 0$ $x = 10~m$ From t = 2 to t = 3 s: $\Delta x = 6~m$ At t = 3 s: $x = 10~m + 6~m$ $x = 16~m$ From t = 3 to t = 4 s: $\Delta x = 10~m$ At t = 4 s: $x = 16~m + 10~m$ $x = 26~m$
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