Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 2 - Kinematics in One Dimension - Exercises and Problems: 4

Answer

At t = 10 s: $v = 1.25~m/s$ At t = 25 s: $v = 0$ At t = 35 s: $v = -5~m/s$

Work Step by Step

The velocity is the slope of the position versus time graph. At t = 10 s: $v = \frac{25~m}{20~s} = 1.25~m/s$ At t = 25 s: $v = 0$ At t = 35 s: $v = \frac{-50~m}{10~s} = -5~m/s$
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