Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 2 - Kinematics in One Dimension - Exercises and Problems - Page 59: 11


(a) $x = 6.0~m$ (b) $v = 4.0~m/s$ (c) $a = 2.0~m/s^2$

Work Step by Step

(a) The area between the velocity versus time graph and the x-axis is equal to the displacement. $\Delta x = 4.0~m$ $x = x_0+\Delta x$ $x = 2.0 + 4.0~m$ $x = 6.0~m$ (b) We can read the value of the velocity directly from the graph. Therefore, $v = 4.0~m/s$ (c) The acceleration is equal to the slope of the velocity versus time graph. Therefore, $a = \frac{6.0~m/s}{3.0~s} = 2.0~m/s^2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.