Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 14 - Fluids and Elasticity - Exercises and Problems - Page 384: 29

Answer

2.12 m/s

Work Step by Step

h=23 cm-0 =$23\times10^{-2}m$ According to Torricelli's law, v= $\sqrt {2gh}$=$\sqrt {2\times9.8 ms^{-2}\times23\times10^{-2}m}=2.12\,m/s$
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