## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

We can let the pressure from the water be equal to the atmospheric pressure. $\rho~g~h = P_0$ $h = \frac{P_0}{\rho~g}$ $h = \frac{1.01\times 10^5~N/m^2}{(1000~kg/m^3)(9.80~m/s^2)}$ $h = 10.3~m$ Therefore, the height of the water is 10.3 m