Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 14 - Fluids and Elasticity - Exercises and Problems - Page 384: 11


The force required to pull the cover off is 630 N

Work Step by Step

We can find the pressure difference between the pressure on the inside of the cover and the pressure on the outside of the cover. $\Delta P = P_0 - P_i$ $\Delta P = (1.01\times 10^5~Pa)-(2.0\times 10^4~Pa)$ $\Delta P = 8.01\times 10^4~Pa$ The can find the force required to pull off the cover. $F = (\Delta P)~(Area~of~the~hole)$ $F = (8.01\times 10^4~N/m^2)(\pi)(0.05~m)^2$ $F = 630~N$ The force required to pull the cover off is 630 N.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.