## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

(a) $I = 0.010~kg~m^2$ (b) $I = 0.030~kg~m^2$
(a) We can find the moment of inertia of the disk for a perpendicular axis through the center. $I = \frac{1}{2}MR^2$ $I = \frac{1}{2}(2.0~kg)(0.10~m)^2$ $I = 0.010~kg~m^2$ (b) We can use the parallel axis theorem to find the moment of inertia about an axis that is through the edge of the disk. Note that the distance $d$ from the center of mass to the edge of the disk is 10 cm. $I = I_{cm}+Md^2$ $I = 0.010~kg~m^2+(2.0~kg)(0.10~m)^2$ $I = 0.030~kg~m^2$