Answer
The angular momentum is $0.025~kg~m^2/s$.
Work Step by Step
We can express the angular velocity in units of rad/s as:
$\omega = (600~rpm)(\frac{2\pi~rad}{1~rev})(\frac{1~min}{60~s})$
$\omega = 20\pi~rad/s$
We then find the moment of inertia of the disk;
$I = \frac{1}{2}MR^2$
$I = \frac{1}{2}(2.0~kg)(0.020~m)^2$
$I = 4.0\times 10^{-4}~kg~m^2$
Next, we find the angular momentum about the axle:
$L = I~\omega$
$L = (4.0\times 10^{-4}~kg~m^2)(20\pi~rad/s)$
$L = 0.025~kg~m^2/s$
The angular momentum is $0.025~kg~m^2/s$.
