Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 12 - Rotation of a Rigid Body - Exercises and Problems - Page 332: 44


The angular momentum is $2.1~kg~m^2/s$

Work Step by Step

We can express the angular velocity in units of rad/s $\omega = (120~rpm)(\frac{2\pi~rad}{1~rev})(\frac{1~min}{60~s})$ $\omega = 4\pi~rad/s$ We can find the moment of inertia of the bar. $I = \frac{1}{12}MR^2$ $I = \frac{1}{12}(0.50~kg)(2.0~m)^2$ $I = 0.167~kg~m^2$ We can find the angular momentum about the axle. $L = I~\omega$ $L = (0.167~kg~m^2)(4\pi~rad/s)$ $L = 2.1~kg~m^2/s$ The angular momentum is $2.1~kg~m^2/s$.
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