## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Let $T_c$ be the tension in the cable car's cable. Let $T_b$ be the tension in the cable attached to the 2000-kg block. Then $T_b$ is equal to the weight of the 2000-kg block. From the diagram, we can see that the horizontal forces exerted on the cart are in equilibrium. We can use this fact to find the tension in the cable car's cable. Therefore; $2~T_c = T_b$ $2~T_c = (2000~kg)(9.80~m/s^2)$ $T_c = \frac{(2000~kg)(9.80~m/s^2)}{2}$ $T_c = 9800~N$ The tension in the cable car's cable is 9800 N.