Answer
(a) A force of 20 N pulls forward on the ice.
(b) A force of 21 N pulls forward on the rope.
Work Step by Step
(a) Let $F_i$ be the force that pulls forward on the ice. We can find the magnitude of $F_i$. Let $m_i$ be the mass of the ice.
$F_i = m_i~a$
$F_i = (10~kg)(2.0~m/s^2)$
$F_i = 20~N$
A force of 20 N pulls forward on the ice.
(b) Let $F_r$ be the force that pulls forward on the rope. We can find the magnitude of $F_r$. Let $m_i$ be the mass of the ice. Let $m_r$ be the mass of the rope.
$F_r = (m_i+m_r)~a$
$F_r = (10~kg+0.50~kg)(2.0~m/s^2)$
$F_r = 21~N$
A force of 21 N pulls forward on the rope.
