The tension in the rope is 590 N
Work Step by Step
The weight of the 60-kg person pulls down on the left side. However, the weight of the 100-kg block is on the right side. Therefore, the system will not start moving and the acceleration of the system is zero. We can consider the system of the person to find the tension in the rope. Let $m_p$ be the mass of the person. $\sum F = m_p~a$ $mg-T = (60~kg)(0)$ $T = mg$ $T = (60~kg)(9.80~m/s^2)$ $T = 590~N$ The tension in the rope is 590 N.