Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 7 - Newton's Third Law - Exercises and Problems - Page 186: 12


The tension in the rope is 590 N

Work Step by Step

The weight of the 60-kg person pulls down on the left side. However, the weight of the 100-kg block is on the right side. Therefore, the system will not start moving and the acceleration of the system is zero. We can consider the system of the person to find the tension in the rope. Let $m_p$ be the mass of the person. $\sum F = m_p~a$ $mg-T = (60~kg)(0)$ $T = mg$ $T = (60~kg)(9.80~m/s^2)$ $T = 590~N$ The tension in the rope is 590 N.
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