Answer
a) $12.5 m$
b) $42.5s$
Work Step by Step
a) We have $v_{max} = 5.0ms^{-1} , u= 0$ and $ a=1ms^{-2}$
thus
$ 2as = v^2 -u^2$
$ 2s = 25 -0$
$ s= 12.5m$
b) time taken to attain its maximum speed(travel $12.5m$
)
$ t_1 = v_{max}/a =5/1 s$
$t_1 =5s$
time taken to complete rest distance at $v_{max}$
$ t_2 = \frac{200m-12.5m}{5ms^{-1}}$
$t_2 = 37.5s$
total time taken to complete whole trip is $t_1 + t_2 =42.5s$
