Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 6 - Dynamics I: Motion Along a Line - Exercises and Problems - Page 164: 51

Answer

Depth of the lake is $30m$

Work Step by Step

let $v$ be the velocity of ball with which it hits the water. So we have $ v^2 - u^2 =2as_1$ $u=0$ ,$s_1 = 5.0m$ and $ a= g = 9.8ms^{-2}$ thus $ v^2 - 0 = (2* 10 * 5 )m^2s^{-2} = 100m^2s^{-2}$ $v= 10ms^{-1}$ let $s_2$ be the depth of lake. therefore $s_2 = v*t$ $v= 10ms^{-1}$ and $t=3.0s$, Thus $s_2 = (10 * 3)m =30m$
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