# Chapter 3 - Vectors and Coordinate Systems - Exercises and Problems: 34

The component of the cannonball's velocity that is parallel to the ground is 86.6 m/s

#### Work Step by Step

The horizontal component of the velocity is parallel to the ground. Therefore; $v_x = v~cos(\theta)$ $v_x = (100~m/s)~cos(30^{\circ})$ $v_x = 86.6~m/s$ The component of the cannonball's velocity that is parallel to the ground is 86.6 m/s.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.