## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

We can find the total displacement that Carlos runs in ten minutes; $d = v~t = (5.0~m/s)(600~s) = 3000~m$ We can find the north component of Carlos' displacement vector; $d_{north} = (3000~m)~sin(25^{\circ})$ $d_{north} = 1268~m$ Carlos ends up 1268 meters north of his starting position.