Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 26 - The Electric Field - Exercises and Problems - Page 776: 25

Answer

$3.1\times 10^{-21}\;\rm N\cdot m$

Work Step by Step

We know that the torque exerted by an electric field on a dipole is given by $$\tau=pE\sin\theta$$ and hence, the maximum torque occurs when $\theta=90^\circ\rightarrow\sin\theta=1$ $$\tau_{max}=pE$$ Plugging the given; $$\tau_{max}=(6.2 \times 10^{-30})(5\times 10^8)$$ $$\tau_{max}=\color{red}{\bf 3.1\times 10^{-21}}\;\rm N\cdot m$$
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