## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

$v = 40~m/s$
We can see that this is the third harmonic since there are 3 antinodes. We can find the wavelength. $\lambda = \frac{2L}{n}$ $\lambda = \frac{(2)(0.60~m)}{3}$ $\lambda = 0.40~m$ We can find the wave speed. $v = f~\lambda$ $v = (100~Hz)(0.40~m)$ $v = 40~m/s$